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Solution
Denote the triangle by ABC where A is the top point C is the bottom left let the midpoint of AC be M and let the midpoint of BC be N now notice that: BM = k = BN \Rightarrow \angle BMN = \angle BNM but from \triangle BMN we can get that \angle BMN = \frac{180^\circ -126^\circ}{2} = 27^\circ But since M,N are midpoints we get that X = \angle BMN = 27^\circ
